Fizzbuzz type question, string searching question, ADT question.

Question

Rain Lawson · Accepted Answer

def fizzBuzz(n):
        """
        :type n: int
        :rtype: List[str]
        """
        numList = []
        for i in range(1, n+1):
            numList.append(i)
        for n, i in enumerate(numlist):
            if (i % 3 == 0) & (i % 5 != 0):
                numList[n] = 'Fizz'
            elif (i % 5 == 0) & (i % 3 != 0):
                numList[n] = 'Buzz'
            elif (i % 3 != 0) & (i % 5 != 0):
                numList[n] = str(i)
            elif (i % 3 == 0) & (i % 5 == 0):
                numList[n] = 'FizzBuzz'

        return numList

IBM

Pregunta de entrevista de IBM

Respuesta de la entrevista

Empresas seguidas

Búsquedas de empleo