Me postulé en línea. El proceso tomó 4 semanas. Acudí a una entrevista en Meta (Dublín, Dublín) en may 2019
Entrevista
I submitted my application a month before I was contacted by email to schedule a phone screening interview. At the time I was on vacation so I couldn't do it in one of the available dates, it was delayed and by the time I said I would be available I was contacted again.
The person I talked to was nice and easy to talk to, didn't make the process too much stressful, either way, I was stressed enough to not be able to answer correctly and I know I wasn't fully prepared for the interview questions.
Preguntas de entrevista [1]
Pregunta 1
What's the space-time complexity of getting an item from a sorted integer array.
Acudí a una entrevista en Meta (Londres, Inglaterra)
Entrevista
Generic LeetCode-style questions, many tagged as Meta, so extensive preparation is required to perform well in the technical interview. The experience varies significantly - some interviewers provide hints and guidance, while others expect candidates to solve problems independently with minimal assistance.
Spoke with interviewer over video conferencing. He was very communicative . He answered my questions. Asked me BFS question. A question that involved BFS search. Given a matrix, I am suppose to find a path from top left to down right.
Preguntas de entrevista [1]
Pregunta 1
A question that involved BFS search. Given a matrix, I am suppose to find a path from top left to down right.
The technical round hit me with a classic array manipulation problem: moving zeroes to the end without disrupting the order of non-zero elements. As I tackled it, I felt a wave of familiarity wash over me; I had just practiced a similar challenge on PracHub. The rest of the interview followed a straightforward path, with some easy behavioral questions sprinkled in. Overall, it felt very easy, but I wasn’t quite the right fit for what they needed, so I didn’t receive an offer.
Preguntas de entrevista [1]
Pregunta 1
Move zeroes in an array to the end while keeping non-zero element order, in place