How to check if a number is even or odd without using % or / ?

Question

Anónimo · Accepted Answer

perform bitwise AND of given number with 1 and check the last bit if it is zero then number is even and if it is 1 then number is odd

Anónimo · Answer

int num;
	cout > num; 

	if ((1 & num) == 1) {
		cout << "Odd 
";
	}
	else {
		cout << "Even 
";
	}

Check this out : · Answer

How if we subtract 2 from given number while x>0. set flag=1 in while loop if x==0 found and break the while loop. Like this : int main() { int x,flag=0; cin>>x; do { x=x-2; if(x==0) { flag=1; break; } }while(x>0); if(flag==1) { cout<<"Even"; } else {cout<<"ODD";} return 0; }

Dheeraj Mandal · Answer

#include
using namespace std;
int main()
{
	int n;
	cout>n;
	bool flag=false;
	//lets do the logic 
	//1.even/odd logic 
	for(int i=2;in)
			{
				break;//break the loop for time complexity
			}
		}
	}
	if(flag)
	{
		cout<<"It is even number"<

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